How do you solve ${log}_{2} x = \frac{1}{3} {log}_{2} 27$ $log_2x=1/3log_2 27$ ?

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How do you solve ${log}_{2} x = \frac{1}{3} {log}_{2} 27$ $log_2x=1/3log_2 27$ ?

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Answer 1 · 2016-06-26T03:11:26

It is

${log}_{2} x = \frac{1}{3} {log}_{2} 27 \Rightarrow {log}_{2} x = \frac{1}{3} \cdot (\frac{log 27}{log 2}) \Rightarrow \frac{log x}{log 2} = \frac{1}{3} \cdot (3 \cdot \frac{log 3}{log 2}) \Rightarrow log x = log 3 \Rightarrow x = 3$ $log_2x=1/3log_2 27=>log_2 x=1/3*(log27/log2)=> logx/log2=1/3*(3*log3/log2)=>logx=log3=>x=3$

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How do you solve ${log}_{2} x = \frac{1}{3} {log}_{2} 27$ $log_2x=1/3log_2 27$ ?

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How do you solve ${log}_{2} x = \frac{1}{3} {log}_{2} 27$ $log_2x=1/3log_2 27$ ?