How do you solve log (2x + 2) – log (x + 6) =0?

1 Answer
Alan P.
Mar 7, 2018

x=4

Explanation:

Note 1:
color(white)("XXX")log(A)-log(B)=log(A/B)
Note 2:
color(white)("XXX")log(1)=0

Therefore
color(white)("XXX")log(2x+2)-log(x+6)=0
can be written as
color(white)("XXX")log((2x+2)/(x+6))=log(1)
which implies
color(white)("XXX")(2x+2)/(x+6)=1

color(white)("XXX")rArr 2x+2=x+6

color(white)("XXX")rArr x=4

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