How do you solve $log_2x+log_2 3=3$ ?

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Answer 1 · 2016-08-21T03:53:24

I found: $x=8/3$

You can condense the two logs and write:
$log_2(3x)=3$
use the definition of log and write:
$3x=2^3$
$3x=8$
$x=8/3$

Answer 2 · 2016-08-21T04:03:33

$x=8/3$

As $2^3=8$ , we have $log_2 8=3$ , hence

$log_2 x+log_2 3=3=log_2 8$ or

$log_2(3×x)=log_2 8$ or

$3x=8$ or

$x=8/3$

How do you solve log_2x+log_2 3=3log_2x+log_2 3=3?