How do you solve $Log_ 3 3^(4x-1) = 15$ ?

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Answer 1 · 2015-12-15T12:20:44

$x=4$

Use the following property of logarithms: $log_a(b^c)=c*log_a b$

Thus, the equation can be rewritten as

$(4x-1)(log_3 3)=15$

Note that $log_3 3=1$ .

$4x-1=15$

$x=4$

How do you solve Log_ 3 3^(4x-1) = 15 Log_ 3 3^(4x-1) = 15?