How do you solve ${log}_{3} (47) = {log}_{8} (x)$ $log_3(47) = log_8(x)$ ?

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Answer 1 · 2018-08-07T08:58:11

$x = 1462.514$ $x=1462.514$

As ${log}_{3} 47 = {log}_{8} x$ $log_3 47=log_8x$ , we have

$\frac{log 47}{log 3} = \frac{log x}{log 8}$ $log47/log3=logx/log8$

or $log x = \frac{log 47}{log 3} \times log 8$ $logx=log47/log3xxlog8$

or $log x = \frac{16721}{0.4771} \times 0.9031 = 3.1651$ $logx=16721/0.4771xx0.9031=3.1651$

and $x = 10^{3.1651} = 1462.514$ $x=10^3.1651=1462.514$

How do you solve log3(47)=log8(x) log_3(47) = log_8(x)?