Question

How do you solve `log_3(x^2) - log_3(x+3) =3`?

Answer 1

`x= (27+-9sqrt5)/2`

Explanation:

LHS= `log_3 ((x^2)/(x+3))`, Hence it is `log_3 ((x^2)/(x+3))`=3

`((x^2)/(x+3))= 3^3 =27`

`x^2 -27x -81=0`

`x= (27+-sqrt (729-324))/2`

`x= (27+-9sqrt5)/2`