How do you solve $log_3 x = 9 log_x 3$ ?

Question

7421 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-18T23:55:48

Using the change of base rule you get

$logx/log3=9log3/logx=>(logx)^2=(3log3)^2=> (logx-3log3)*(logx+3log3)=0=> x=3^3=27 or x=1/27$

How do you solve log_3 x = 9 log_x 3log_3 x = 9 log_x 3?