Question

How do you solve `log(3x+1)=2`?

Answer 1

`x=33`

Explanation:

By definition if `loga=b`, we have `10^b=a`, hence

`log(3x+1)=2`

`hArr(3x+1)=10^2` or

`3x+1=100` or

`3x=100-1` or

`3x=99` or

`x=99/3=33`