How do you solve $log 3x = log 2 + log (x+5)$ ?

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Answer 1 · 2016-01-11T20:26:14

x = 10

using the law that logx + log y = logxy.

on the right hand side : log2 + log(x +5) =log 2(x + 5 )

so we have log3x = log(2x + 10)

$rArr 3x = 2x + 10 rArr 3x - 2x = 10 rArr x = 10$

How do you solve log 3x = log 2 + log (x+5)log 3x = log 2 + log (x+5)?