Question

How do you solve `log_3x=log_3(2x-1)`?

Answer 1

`x=1`

Explanation:

If `log_3 x =log_3 (2x-1)`
then
`color(white)("XXX")x=2x-1`

`color(white)("XXX")0=x-1`

`color(white)("XXX")x=1`