How do you solve #log_4 r=3#?

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Answer 1 · 2016-10-08T08:16:15

#r=64#

From the definition of logarithm, if

#log_4 r=3#, we have

#4^3=r#

Hence #r=64#

Answer 2 · 2016-10-08T08:16:55

# r=64#.

Recall the Defn. of #log# fun.

#" Defn. : "log_b x=m iff b^m=x#

#"Hence, "log_4r=3 rArr 4^3=r#

#:. r=64#.