Question

How do you solve `Log(5(2^x)) = log(3-2^(x+2))`?

Answer 1

`x = log 3/log 2`/

Explanation:

Equating the arguments,

#5( 2^x)=3-2^(x+2 )= 3-2^x2^2 =3-4( 2^x)#

So, `2^x=3` and.

`x log 2 = log 3`
`x=log 3/log 2`.