Question

How do you solve `log_5(3x^2 - 1) = log_5 2x`?

Answer 1

x = 1.

Explanation:

Logarithm is a single-valued function.

So, `3x^2-1=2x`. Solving this quadratic equation

`3x^2-2x-1=0, x = 1. -1/2`

Negative root is inadmissible for #log_5(2x).

So, x = 1.