Question

How do you solve `log_5(4x+11)=2`?

Answer 1

`x = 3 1/2`

Explanation:

Log form and index form are interchangeable.

If `log_a b = c " then "rArr a^c = b`

We have: `log_5 (4x+11) = 2 " then " 5^2 = 4x +11`

`25 = 4x +11`

`14 = 4x`

`x = 3 1/2`