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How do you solve ${log}_{5} (4 x) - {log}_{5} (x - 5) = 2 {log}_{53}$ $log_5(4x) - log_5(x-5) = 2log_53$ ?

1 Answer

May 8, 2015

Are you sure about the last one? Isn't $2 {log}_{5} (3)$ $2log_5(3)$ ?

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