How do you solve $(¼)log_6 (a – 3) – log_6 3 = 0$ ?

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Answer 1 · 2018-07-26T16:55:33

$a=84$

We have ,

$1/4log_6(a-3)-log_6 3=0$

$=>1/4log_6(a-3)=log_6 3$

$=>log_6(a-3)=4log_6 3to["Multiplying both sides by 4]"$

$=>log_6(a-3)=log_6 3^4to[becauselog_k x^n=nlog_k x]$

$=>log_6(a-3)=log_6 81$

$=>a-3=81$

$=>a=81+3$

$=>a=84$

How do you solve (¼)log_6 (a – 3) – log_6 3 = 0 (¼)log_6 (a – 3) – log_6 3 = 0?