Question

How do you solve `log (6x+2) - log (3x-6) = log 6 - log 2`?

Answer 1

20/3

Explanation:

`log(6x+2)-log(3x-6)=log6-log2`
`or,log((6x+2)/(3x-6))=log(6/2)`
`or,(6x+2)/(3x-6)=3` [by, adding antilog to each side]

`or,6x+2=9x-18`

`or,3x=20`
`or,x=20/3`