How do you solve $Log_a X = 3 Log_a 2$ ?

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Answer 1 · 2018-06-22T17:51:18

x=8

just apply $a*log(b)=log(b^a)$
then cancel the $log$ s and you get $x=2^3$ or $x=8$

How do you solve Log_a X = 3 Log_a 2 Log_a X = 3 Log_a 2 ?