How do you solve $log_b(3)=0.381$ ?

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Answer 1 · 2016-05-06T12:02:10

$b = log 3/0.381=1.2523$ , nearly.

Use $log_b a = log a/log b$ .

Here., $log_b 3 = log 3/log b=0.381$ .

So, $log b = log 3/ 0.381=1.2523$ , nearly...

How do you solve log_b(3)=0.381log_b(3)=0.381?