How do you solve $log (log (x)) = 1$ $Log(log(x)) =1$ ?

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Answer 1 · 2015-12-03T00:58:26

exponentiate ...

Let's assume that log is base e ...

$e^{log (log (x))} = e^{1}$ $e^(log(log(x)))=e^1$

simplify ...

$log x = e$ $logx=e$

exponentiate again ...

$e^{log x} = e^{e}$ $e^logx=e^e$

$x = e^{e} \approx 15.154$ $x=e^e~~15.154$

hope that helped

How do you solve log(log(x))=1Log(log(x)) =1?