How do you solve #Log(log(x)) =1#?

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Answer 1 · 2015-12-03T00:58:26

exponentiate ...

Let's assume that log is base e ...

#e^(log(log(x)))=e^1#

simplify ...

#logx=e#

exponentiate again ...

#e^logx=e^e#

#x=e^e~~15.154#

hope that helped