How do you solve $log m = log 2 + log 14$ $Log m = Log 2 + Log 14$ ?

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Answer 1 · 2016-04-21T17:40:51

$m = 28$ $m=28$

Use Property ${log}_{b} (x y) = {log}_{b} x + {log}_{b} y$ $log_b(xy)=log_bx+log_by$

$log m = log (2 \cdot 14)$ $log m=log(2*14)$

$log m = log 28$ $log m = log 28$

$m = 28$ $m=28$

How do you solve Log m = Log 2 + Log 14logm=log2+log14Log m = Log 2 + Log 14?