How do you solve $Log(x)= -0.123$ ?

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Answer 1 · 2016-04-23T06:52:42

$x=10^(=0.123)=0.7534$ , nearly.

For logarithm, with any base b,

if $c=log_b a$ ,

then the inverse relation is

$a=b^c$

For common logarithms, b =10 and b is in hiding..

So, here, $x=10^(-0.123)=0.7534$ , nearly.

How do you solve Log(x)= -0.123Log(x)= -0.123?