Question

How do you solve `log(x+10)-log(x+4)=logx`?

Answer 1

It is `x=2`

Explanation:

It is

#log(x+10)-log(x+4)=logx=>log[(x+10)/(x+4)]=logx=> (x+10)/(x+4)=x=>x+10=x*(x+4)=> x^2+4x-x-10=0=> x^2+3x-10=0=> x_1=2 or x_2=-5#

But hence `x>0` the only acceptable solution is `x=2`