How do you solve ${log x}^{2} = 2$ $log x^2 =2$ ?

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Answer 1 · 2015-10-23T16:31:35

$x = 10$ $x=10$

By using laws of logs, we can write this as

$2 log x = 2$ $2 log x = 2$

Now dividing by 2 on both sides we get

$log x = 1$ $logx=1$

Now using the definition of log function we obtain

$x = 10^{1} = 10$ $x=10^1=10$

How do you solve logx2=2log x^2 =2?