How do you solve $log x^2 =2$ ?

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Answer 1 · 2015-12-02T07:47:29

Apply the exponential function and use a property of logarithms to find that
$x = +-e$

For this problem, we will use that
$e^log(a) = a$

$log(x^2) = 2$

$=> e^log(x^2) = e^2$

$=> x^2 = e^2$

$=> sqrt(x^2) = sqrt(e^2)$

$=> |x| = e$

$=> x = +-e$

How do you solve log x^2 =2log x^2 =2?