How do you solve ${log x}^{2} + log 25 = 2$ $log x^2 + log 25 = 2$ ?

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How do you solve ${log x}^{2} + log 25 = 2$ $log x^2 + log 25 = 2$ ?

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Answer 1 · 2015-09-11T02:13:44

The answer is $x = 2$ $x=2$

Explanation:

We have that

${log x}^{2} + log 25 = 2 \Rightarrow log 25 x^{2} = log 100 \Rightarrow 25 x^{2} = 100 \Rightarrow x^{2} = 4 \Rightarrow x = 2, x = - 2$ $logx^2+log25=2=>log25x^2=log100=>25x^2=100=>x^2=4=>x=2,x=-2$

But $x > 0$ $x>0$ hence $x = 2$ $x=2$

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How do you solve ${log x}^{2} + log 25 = 2$ $log x^2 + log 25 = 2$ ?

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How do you solve ${log x}^{2} + log 25 = 2$ $log x^2 + log 25 = 2$ ?