How do you solve $log x^2 = (log x)^2$ ?

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Answer 1 · 2015-12-01T18:54:36

$1 or e^2$

$y = log x$

$2y = y^2$

$y = 0 or y = 2$

$log x = 0 or log x = 2$

$x = e^0 or x = e^2$

How do you solve log x^2 = (log x)^2 log x^2 = (log x)^2?