How do you solve $Log(x)-2=log(x-4)$ ?

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Answer 1 · 2018-03-28T16:44:31

x=4/99

$log(x)-2=log(x-4)$

$x/10^2=x-4,iff x>0 and x>4$

$x/10^2-x=-4$

$x-100x=-400$

$-99x=-400$

$x=400/99$

x>4 so the solution is correct.

How do you solve Log(x)-2=log(x-4)Log(x)-2=log(x-4)?