How do you solve #log x=3#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Lovecraft Sep 17, 2015 #x = 1000# Explanation: Remember the definition of logarithm, that is If #log_b(a) = c# is true, then #a = b^c#, and if no base is explicitly put we always assume it's the base 10 (unless it's written as #lnx# in which case the base is the irrational number #e#) #logx = 3 rarr x = 10^3 rarr x = 1000# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 8717 views around the world You can reuse this answer Creative Commons License