Question

How do you solve `log(x - 3) = 1 - log(x)`?

Answer 1

`=>x_1=-2, x_2=5`

Explanation:

`log(x+3)=1-log(x)`
`=>log(x+3)+log(x)=1-log(x)+log(x)`
The logarithm of a product is the sum of the logarithms of the numbers being multiplied:
`log(x^2-3x)=1`
`=>x^2-3x=10`
`=>x^2-3x-10=10-10`
`=>x^2-3x-10=0`
`=>(x-5)(x+2)=0`
`=>x_1=-2, x_2=5`