How do you solve log (x+3)=log 8-log 2?

1 Answer
Feb 28, 2016

x=1

Explanation:

What you need to know:
color(white)("XXX")log(p) - log(q) = log (p/q)

Therefore:
color(white)("XXX")log(x+3)=log(8)-log(2)

rarrcolor(white)("XXX")log(x+3) = log(4)

rarrcolor(white)("XXX")x+3 = 4

rarrcolor(white)("XXX")x=1