How do you solve $log (x - 5) = - 2$ $log(x-5)=-2$ ?

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Answer 1 · 2016-07-18T13:58:16

$x = 5.01$ $x=5.01$ .

By defn. of $log$ $log$ function, $log t = m \Leftrightarrow t = 10^{m}$ $logt=m iff t=10^m$

$:. log(x-5)=-2 rArr x-5=10^-2=0.01$

$:. x=5+0.01=5.01$ .

How do you solve log(x-5)=-2log(x−5)=−2log(x-5)=-2?