How do you solve log(x) + log(2x + 1) = 1?

1 Answer
Özgür Özer
Dec 27, 2015

color(white)xxx_1=2
color(white)xxx_2=-5/2

Explanation:

color(white)xxlogx+log(2x+1)=1

=>logx(2x+1)=1
=>2x^2+x=10
=>2x^2+x-10=0

color(white)xxDelta=81
=>x_(1,2)=(-1+-9)/4

=>x_1=2
=>x_2=-5/2

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