How do you solve $log x + log 4 = log (x + 9)$ $log x + log 4 = log (x + 9)$ ?

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Answer 1 · 2015-11-30T23:12:23

Use the properties of logs ...

$log x + log 4 = log 4 x = log (x + 9)$ $logx+log4=log4x=log(x+9)$

Next, set arguments equal to each other ...

$4 x = x + 9$ $4x=x+9$

Finally, solve for x ...

$3 x = 9$ $3x=9$

ANSWER : $x = 3$ $x=3$

hope that helped

How do you solve logx+log4=log(x+9) log x + log 4 = log (x + 9)?