How do you solve $log x - log (8 - 5 x) = 2$ $log x - log(8-5x) = 2$ ?

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Answer 1 · 2018-05-24T01:52:44

$log x - log (8 - 5 x) = 2$ $logx-log(8-5x)=2$

$\Rightarrow {log}_{10} (\frac{x}{8 - 5 x}) = 2$ $=>log_10(x/(8-5x))=2$

$\Rightarrow \frac{x}{8 - 5 x} = 100$ $=>x/(8-5x)=100$

$\Rightarrow x = (8 - 5 x) \cdot 100$ $=>x=(8-5x)*100$

$\Rightarrow x = 800 - 500 x$ $=>x=800-500x$

$\Rightarrow 501 x = 800$ $=>501x=800$

$\Rightarrow x = \frac{800}{501}$ $=>x=800/501$

How do you solve log x - log(8-5x) = 2logx−log(8−5x)=2log x - log(8-5x) = 2?