How do you solve ${log}_{x} 4 + {log}_{x} 9 = 2$ $log_x4 + log_x9=2$ ?

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Answer 1 · 2016-04-21T16:56:35

$x = 6$ $x=6$

${log}_{x} (4 \cdot 9) = 2$ $log_x (4*9)=2$

${log}_{x} 36 = 2$ $log_x 36 =2$

$x^{2} = 36$ $x^2 =36$

$x = 6$ $x=6$

How do you solve logx4+logx9=2log_x4 + log_x9=2?