Question

How do you solve `log y = log (x-1) + 1`?

Answer 1

y = `10 (x-1)`, x > 1.

Explanation:

Working on common logarithm, `y = 10^((log(x-1)+1)`.
`10^(m+n)= 10^m 10^n` and `10^(log a)=a`.
`y = (x-1) X 10^1=10(x-1)`
Here, `log(x-1)` is defined for x > 1. So, the answer is suject yo x > 1..