How do you solve $log 3 (x + 1) - log 5 (x - 2) = 2$ $log3(x+1) - log5(x-2)=2$ ?

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Answer 1 · 2016-05-06T17:36:45

$x = \frac{497}{1003}$ $x=497/1003$

$log 3 (x + 1) - log 5 (x - 2) = 2$ $log3(x+1)-log5(x-2)=2$

or $\frac{log (3 (x + 1))}{5 (x - 2)} = log 100$ $log(3(x+1))/(5(x-2))=log100$

or $\frac{3 (x + 1)}{5 (x - 2)} = 100$ $(3(x+1))/(5(x-2))=100$

or $3 x + 3 = 100 \times (5 x - 10)$ $3x+3=100xx(5x-10)$

or $3 x + 3 = 500 x - 1000$ $3x+3=500x-1000$

or $497 x = 1003$ $497x=1003$

or $x = \frac{497}{1003}$ $x=497/1003$

How do you solve log3(x+1)−log5(x−2)=2log3(x+1) - log5(x-2)=2?