How do you solve log3x=log4+log(x+3)?

1 Answer
Apr 19, 2016

x > 0. The negative solution x=12 is inadmissible for the given equation. So there is no real solution.

Explanation:

x > 0.
Use logalogb=log(ab)

log(3xx+3)=log4

Som 3xx+3=4

x=12.

As x > 0 for log x, x=12 is inadmissible.