Question

How do you solve `Log3x=log4+log(x+3)`?

Answer 1

x > 0. The negative solution `x = -12` is inadmissible for the given equation. So there is no real solution.

Explanation:

x > 0.
Use `log a - log b = log (a/b)`

`log ((3x)/(x+3))=log 4`

Som `(3x)/(x+3)=4`

`x = -12`.

As x > 0 for log x, `x = -12` is inadmissible.