Question

How do you solve `log7 + log (n - 2) = log 6n`?

Answer 1

`n= 14`

Explanation:

We have:

`log7 + log (n - 2) = log 6n`

Using the log properties:

`log ab = log a + logb`
`log a = log b iff a=b`

So that:

`log 7(n - 2) = log 6n`

`:. 7(n - 2) = 6n`

`:. 7n-14 = 6n`
`:. 7n-6n = 14`
`:. n= 14`