How do you solve ${log 8}^{w} = 3$ $log8^w=3$ ?

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Answer 1 · 2015-06-07T22:46:43

$w = \frac{3}{log (8)}$ $w = 3/(log(8)$

Assuming $log$ $log$ without a subscript is referring to ${log}_{10}$ $log_10$ :

${log (8)}^{w} = 3$ $log(8)^w = 3$

$w \cdot log (8) = 3$ $w* log(8) = 3$

$w = \frac{3}{log (8)}$ $w = 3/(log(8)$

How do you solve log8w=3log8^w=3?