Question

How do you solve `logx + log(x-3) = 1`?

Answer 1

I found `x=5`

Explanation:

You csn use a rule of logs and get:
`logx(x-3)=1`
If your logs are in base `10` you can write:
`x(x-3)=10^1`
`x^2-3x=10`
`x^2-3x-10=0`
Using the Quadratic Formula:
`x_(1,2)=(3+-sqrt(9+40))/2=(3+-7)/2`
So:
`x_1=5`
`x_2=-2` No