How do you solve $logx = log5 + 3log3$ ?

Question

2627 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-21T17:47:29

$x=135$

$log x= log 5 + log 3^3$

$log x = log5 + log 27$

$log x=log (5*27)$

$log x=log 135$

$x=135$

How do you solve logx = log5 + 3log3logx = log5 + 3log3?