How do you solve $log x - log 6 = 2 log 4$ $logx-log6=2log4$ ?

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Answer 1 · 2016-10-25T18:36:04

$x = 96$ $x=96$

$log x - log 6 = 2 log 4$ $logx-log6=2log4$

$\Rightarrow log x = {log 4}^{2} + log 6$ $=>logx=log4^2+log6$

$\Rightarrow log x = log 16 + log 6 = log (16 \times 6)$ $=>logx=log16+log6=log(16xx6)$

$\Rightarrow log x = log 96$ $=>logx=log96$

$:. x=96$

How do you solve logx-log6=2log4logx−log6=2log4logx-log6=2log4?