How do you solve $n^2+4n-3=2$ by completing the square?

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Answer 1 · 2015-07-10T22:06:58

Solve: $y = n^2 + 4n - 3 = 2.$

n^2 + 4n - 5 = 0
$n^2 + 4n = 5$
$n^2 + 4n + 4 = 5 + 4$
$(n + 2)^2 = 9 -> (n + 2) = +- 3$

$n = - 2 +- 3$ -> n = 1 and n = - 5

How do you solve n^2+4n-3=2n^2+4n-3=2 by completing the square?