How do you solve $p^2-3p-88=0$ ?

Question

2199 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-22T09:05:31

$p=11$

$p=-8$

$p^2-3p-88=0$

or

$p^2-11p+8p-88=0$

or

$p(p-11)+8(p-11)=0$

or

$(p-11)(p+8)=0$

or

$p-11=0$

or

$p=11$ ----------------------Ans $1$

or

$p+8=0$

or

$p+8=0$

or

$p=-8$ -------------------------Ans $2$

How do you solve p^2-3p-88=0p^2-3p-88=0?