How do you solve sqrt(3x+10) = x+23x+10=x+2?

2 Answers
Aug 13, 2016

x = -3 or +2x=3or+2

Explanation:

sqrt(3x+10) = x+23x+10=x+2

Square both sides:
3x+10 = (x+2)^23x+10=(x+2)2

3x+10 = x^2 + 4x +43x+10=x2+4x+4

x^2+x-6=0x2+x6=0

(x+3)(x-2) = 0(x+3)(x2)=0

Therefore:

Either (x+3)= 0 -> x=-3(x+3)=0x=3
Or (x-2) = 0 -> x=+2(x2)=0x=+2

Aug 13, 2016

x=2 or x=-3x=2orx=3

Explanation:

sqrt(3x+10)=x+23x+10=x+2 ; squaring both sides 3x+10=(x+2)^2 or x^2+4x+4-3x-10=0 orx^2+x-6=0 or x^2+3x-2x-6=0 or x(x+3)-2(x+3)=0 or(x+3)(x-2)=0 :. x+3=0 or x=-3; x-2=0 or x=2[Ans]