How do you solve #sqrt(6x - 8) = x #?
1 Answer
Oct 2, 2017
Explanation:
Given:
#sqrt(6x-8) = x#
Note that
Square both sides of the given equation (noting that this may introduce extraneous solutions), to get:
#6x-8 = x^2#
Subtract
#0 = x^2-6x+8 = (x-4)(x-2)#
So:
#x = 2" "# or#" "x = 4#
Since these are both positive, they are both solutions of the original equation.