How do you solve #sqrt(u+6)=u# and check your solution?
1 Answer
Jul 13, 2017
Explanation:
There are two possibilities:
To check your solutions, substitute them back into the original equation.
#sqrt(u+6)=u#
#sqrt(3+6)=3#
#sqrt(9)=3#
#3=3# #-># works
#sqrt(u+6)=u#
#sqrt(-2+6)=-2#
#sqrt(4)=-2#
#2=-2# #-># does not work
So, the only solution is