How do you solve #sqrt(x) + 1=5#?

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Answer 1 · 2017-05-30T18:26:57

See a solution process below:

First, subtract #color(red)(1)# from each side of the equation to isolate the radical while keeping the equation balanced:

#sqrt(x) + 1 - color(red)(1) = 5 - color(red)(1)#

#sqrt(x) + 0 = 4#

#sqrt(x) = 4#

Now, square each side of the equation to solve for #x# while keeping the equation balanced:

#(sqrt(x))^2 = 4^2#

#x = 16#